Question

The position-time graph of a particle of mass $ 4 \,kg $ is shown in the figure. Calculate the impulse (in $ MKS $ units) at time $ t = 0 $ and $ t = 6 \,$ seconds respectively

• A. +6.31 and - 6.31
• B. +3.33 and -3.33
• C. +6.33 and -6.33
• D. +3.25 and -3.25

Answer 1

Answer: (B)

The position-time graph gives the velocity

According to this graph, velocity at $t = 6 \,s$
$v = \frac{5}{6} m/s$
Impulse $=$ Change in momentum
$ = m_1v_2 - m_2v_1$
$ = 4\times 5/6 - 4 \times 0$
$ = 20/6 = 3.33$
So option (b) is correct.