Q.
The point of inflexion on the curve y=x5/3 will be
3353
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Rajasthan PETRajasthan PET 2004
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Solution:
Given, y=x5/3 ⇒dxdy=35x2/3
For the point of inflexion, dxdy=0 ⇒35x2/3=0 ⇒x=0 ⇒y=0 So, point is (0, 0)
Now, dx2d2y=35.32x−1/3 (dx2d2y)x=0=0
Hence, point of inflexion does not exist.