The photograph of a house occupies an area of 1.75 cm 2 on a 35 mm slide. The slide is projected on to a screen and the area of the house on the screen is 1.55 m 2 . The linear magnification of the projector-screen arrangement, is

Question

The photograph of a house occupies an area of 1.75 cm 2 on a 35 mm slide. The slide is projected on to a screen and the area of the house on the screen is 1.55 m 2 . The linear magnification of the projector-screen arrangement, is (A) 84.1 (B) 96.1 (C) 94.1 (D) 86.1

Tardigrade Admin · Accepted Answer

Area of object =1.75 cm 2=1.75 × 10-4 m 2 Area of image =1.55 m 2 ∴ Areal magnification =( text Area of image / text Area of object ) =(1.55/1.75 × 10-4) ≈ 8857 Linear magnification =√ text Area magnification =√8857=94.1

Q. The photograph of a house occupies an area of $1.75 c m^{2}$ on a $35 mm$ slide. The slide is projected on to a screen and the area of the house on the screen is $1.55 m^{2} .$ The linear magnification of the projector-screen arrangement, is

84.1

96.1

94.1

86.1

Area of object $= 1.75 c m^{2} = 1.75 \times 1 0^{- 4} m^{2}$
Area of image $= 1.55 m^{2}$
$∴$ Areal magnification $= \frac{Area of image}{Area of object}$
$= \frac{1.55}{1.75 \times 1 0 ^{- 4}} \approx 8857$
Linear magnification $= Area magnification$
$= 8857 = 94.1$

Q. The photograph of a house occupies an area of 1.75cm2 on a 35mm slide. The slide is projected on to a screen and the area of the house on the screen is 1.55m2. The linear magnification of the projector-screen arrangement, is