The photoelectric cut off voltage in a certain experiment is 1.5 V. The maximum kinetic energy of photoelectrons emitted is

Question

The photoelectric cut off voltage in a certain experiment is 1.5 V. The maximum kinetic energy of photoelectrons emitted is (A) 2.4 eV (B) 1.5 eV (C) 3.1 eV (D) 4.5 eV

Tardigrade Admin · Accepted Answer

Here, V0=1.5 V, Maximum kinetic energy =eV0=1.5 eV

Q. The photoelectric cut off voltage in a certain experiment is $1.5 V$ . The maximum kinetic energy of photoelectrons emitted is

$2.4 e V$

$1.5 e V$

$3.1 e V$

$4.5 e V$

Here, $V_{0} = 1.5 V$ ,
Maximum kinetic energy $= e V_{0} = 1.5 e V$

Q. The photoelectric cut off voltage in a certain experiment is 1.5V. The maximum kinetic energy of photoelectrons emitted is

2.4eV

1.5eV

3.1eV

4.5eV