Question

The $pH$ value of $1/1000N-KOH$ solution is :

• A. $3$
• B. $10^{11}$
• C. $2$
• D. $11$

Answer 1

Answer: (D)

In $\frac{N}{1000}KOH$ solution, $\left[O{H}^{-}\right]=10^{-3}M$
$pOH=-log\left(O{H}^{-}\right)=-log\left[10^{-3}\right]$
$=+3log10$
$=3$
$pH+pOH=14$
$pH=14-pOH$
$=14-3=11$