Question

The pH value of 0.01 N NaOH solution is

• A. 2
• B. 6
• C. 12
• D. 11

Answer 1

Answer: (C)

Given, NaOH = 0.01 N
$[O{H}^{-}]=0.01N=1\times 10^{-2}$
$pOH=-log[O{H}^{-}]$
$=-log(1\times 10^{-2})$
$=2$
pH+ pOH=14
pH+ 2=14
$\therefore pH=12$