Question

The pH of a solution containing $40$ milligrams of sodium hydroxide in $10d{m}^3$ of the solution is

• A. 9
• B. 10
• C. 11
• D. 12

Answer 1

Answer: (B)

Concentration of $NaOH$ solution
$=\frac{40\times 10^{-3}}{40\times 10}mol/L=10^{-4}mol/L$
Hence, $pOH=4$ and $pH=14-4=10$