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Tardigrade
Question
Chemistry
The pH of 0.10 N acetic acid having Ka=1.8 × 10-5 is
Q. The
p
H
of
0.10
N
acetic acid having
K
a
=
1.8
×
1
0
−
5
is
689
162
Equilibrium
Report Error
A
2.9
B
5.6
C
6.8
D
3.4
Solution:
∴
[
H
+
]
=
C
α
or
C
⋅
C
K
a
=
K
a
C
[
∵
α
=
c
K
a
]
⇒
1.8
×
1
0
−
5
×
0.1
=
1.34
×
1
0
−
3
M
⇒
p
H
=
−
lo
g
[
H
+
]
=
−
lo
g
(
1.34
×
1
0
−
3
)
=
2.9