Question

The pH of 0.01 M NaOH (aq) solution will be

• A. 7.01
• B. 2
• C. 12
• D. 9

Answer 1

Answer: (C)

$NaOH(aq)$ is strong base solution
So, $[O{H}^{-}]=N=10^{-2}N$
$pOH=-log[O{H}^{-}]=-log10^{-2}=2$
$pH=14-pOH=14-2$
$pH=12$