Question

The period of oscillation of a simple pendulum in the experiment is recorded as $2.63s,2.56s,2.42s,2.71$ s and $2.80s$ respectively. The average absolute error is

• A. 0.1 s
• B. 0.11 s
• C. 0.01 s
• D. 1.0 s

Answer 1

Answer: (B)

Average value $=\frac{2.63+2.56+2.42+2.71+2.80}{5}=2.62s$

Now $\left|\Delta T_1\right|=2.63-2.62=0.01$

$\left|\Delta T_2\right|=2.62-2.56=0.06$

$\left|\Delta T_3\right|=2.62-2.42=0.20$

$\left|\Delta T_4\right|=2.71-2.62=0.09$

$\left|\Delta T_5\right|=2.80-2.62=0.18$

Mean absolute error

$\Delta T=\frac{|\Delta T_1|+|\Delta T_2|+|\Delta T_3|+|\Delta T_4|+|\Delta T_5|}{5}$

$=\frac{0.54}{5}=0.108=0.11s$