The percentage of Se in peroxides enzyme is 0.5% by mass (atomic mass of Se = 78.4 amu). Then, the minimum molecular mass of enzyme which contains not more than one Se atom is

Question

The percentage of Se in peroxides enzyme is 0.5% by mass (atomic mass of Se = 78.4 amu). Then, the minimum molecular mass of enzyme which contains not more than one Se atom is (A) 1.568× 104amu (B) 1.568× 107 amu (C) 1.568× 103 amu (D) 1.568× 106 amu

Tardigrade Admin · Accepted Answer

In peroxidase anhydrous enzyme, 0.5 gm Se is present in 100 gm of the enzyme. In a molecule of enzyme, one Se atom must be present. Hence 78.4gm Se will be present in (100/0.5) × 78.4=1.568 × 104

Q. The percentage of Se in peroxides enzyme is 0.5% by mass (atomic mass of Se = 78.4 amu). Then, the minimum molecular mass of enzyme which contains not more than one Se atom is

$1.568 \times 1 0^{4} am u$

$1.568 \times 1 0^{7}$ amu

$1.568 \times 1 0^{3}$ amu

$1.568 \times 1 0^{6}$ amu

In peroxidase anhydrous enzyme, $0.5 g m$
Se is present in $100 g m$ of the enzyme.
In a molecule of enzyme, one Se atom must be present.
Hence 78.4gm Se will be present in $\frac{100}{0.5} \times 78.4 = 1.568 \times 1 0^{4}$

Q. The percentage of Se in peroxides enzyme is 0.5% by mass (atomic mass of Se = 78.4 amu). Then, the minimum molecular mass of enzyme which contains not more than one Se atom is

1.568×104amu

1.568×107 amu

1.568×103 amu

1.568×106 amu

In peroxidase anhydrous enzyme, 0.5gm Se is present in 100gm of the enzyme. In a molecule of enzyme, one Se atom must be present. Hence 78.4gm Se will be present in 0.5100​×78.4=1.568×104

$1.568 \times 1 0^{4} am u$

$1.568 \times 1 0^{7}$ amu

$1.568 \times 1 0^{3}$ amu

$1.568 \times 1 0^{6}$ amu

In peroxidase anhydrous enzyme, $0.5 g m$
Se is present in $100 g m$ of the enzyme.
In a molecule of enzyme, one Se atom must be present.
Hence 78.4gm Se will be present in $\frac{100}{0.5} \times 78.4 = 1.568 \times 1 0^{4}$