The percentage of C, H and N in an organic compound are 40 %, 13.3 % and 46.7 % respectively then emprirical formula is :

Question

The percentage of C, H and N in an organic compound are 40 %, 13.3 % and 46.7 % respectively then emprirical formula is : (A) C3H13N3 (B) CH2N (C) CH4N (D) CH6N

Tardigrade Admin · Accepted Answer

Table for empirical formula Hence, empirical formula is CH4N.

Q. The percentage of $C, H$ and $N$ in an organic compound are $40%$ , $13.3%$ and $46.7%$ respectively then emprirical formula is :

$C_{3} H_{1} 3 N_{3}$

$C H_{2} N$

$C H_{4} N$

$C H_{6} N$

Table for empirical formula
Hence, empirical formula is CH $_{4}$ N.

Q. The percentage of C,H and N in an organic compound are 40%, 13.3% and 46.7% respectively then emprirical formula is :

C3​H1​3N3​

CH2​N

CH4​N

CH6​N