The peak value of an alternating emf E given by E=E0 cos ω t is 10 V and its frequency is 50 Hz. At a time t=(1/600) s, the instantaneous value of the emf is

Question

The peak value of an alternating emf E given by E=E0 cos ω t is 10 V and its frequency is 50 Hz. At a time t=(1/600) s, the instantaneous value of the emf is (A) 10 V (B)  5√3 V  (C) 5 V (D) 1 V

Tardigrade Admin · Accepted Answer

E=E0 cos ω t=10 cos (2 π × f t) =10 cos (2 π × 50 × (1/600)) =10 cos ((π/6))=10 × (√3/2)=5 √3 V

Q. The peak value of an alternating emf $E$ given by $E = E_{0} cos ω t$ is $10 V$ and its frequency is $50 Hz$ . At a time $t = \frac{1}{600} s$ , the instantaneous value of the emf is

$10 V$

$53 V$

$5 V$

$1 V$

$E = E_{0} cos ω t = 10 cos (2 π \times f t)$
$= 10 cos (2 π \times 50 \times \frac{1}{600})$
$= 10 cos (\frac{π}{6}) = 10 \times \frac{3}{2} = 53 V$

Q. The peak value of an alternating emf E given by E=E0​cosωt is 10V and its frequency is 50Hz. At a time t=6001​s, the instantaneous value of the emf is

10V

53​V

5V

1V