The partial pressure of hydrogen in a flask containing 2 g H 2 and 32 g SO 2 is

Question

The partial pressure of hydrogen in a flask containing 2 g H 2 and 32 g SO 2 is (A) 1 / 16 text th of total pressure (B) 1 / 9 text th of total pressure (C) 2 / 3 text nd of total pressure (D) 1 / 8 text th of total pressure

Tardigrade Admin · Accepted Answer

Let total pressure be PT Then, P H 2= P T chi H 2 Where, chi H 2=( n H 2/ n H 2+ n O 2) n H 2=(2 g /2 g mol -1)=1 mol n SO 2=(32 g /64 g mol -1)=(1/2) mol ∴ n H 2=(1/1+(1)2)=(2/3) P H 2=(2/3) P T i.e., (2/3) rd of total pressure.

Q. The partial pressure of hydrogen in a flask containing $2 g H_{2}$ and $32 g S O_{2}$ is

$1/1 6^{th}$ of total pressure

$1/ 9^{th}$ of total pressure

$2/ 3^{nd}$ of total pressure

$1/ 8^{th}$ of total pressure

Q. The partial pressure of hydrogen in a flask containing 2gH2​ and 32gSO2​ is

1/16th of total pressure

1/9th of total pressure

2/3nd of total pressure

1/8th of total pressure

Let total pressure be PT​ Then, PH2​​=PT​χH2​​ Where, χH2​​=nH2​​+nO2​​nH2​​​ nH2​​=2gmol−12g​=1mol nSO2​​=64gmol−132g​=21​mol ∴nH2​​=1+21​1​=32​ PH2​​=32​PT​ i.e., 32​rd of total pressure.

Q. The partial pressure of hydrogen in a flask containing $2 g H_{2}$ and $32 g S O_{2}$ is

$1/1 6^{th}$ of total pressure

$1/ 9^{th}$ of total pressure

$2/ 3^{nd}$ of total pressure

$1/ 8^{th}$ of total pressure