The paramagnetic behaviour of B2 is due to the presence of

Question

The paramagnetic behaviour of B2 is due to the presence of (A) 2 unpaired electrons in πb MO (B) 2 unpaired electrons in π* MO (C) 2 unpaired electrons in σ * MO (D) 2 unpaired electrons in σb MO

Tardigrade Admin · Accepted Answer

B 2=5+5 =10 e- =σ 1 s2 overset*σ 1 s2, σ 2 s2 σ 2 s2, π 2 px1, π 2 py1 Due to the presence of 2 unpaired electrons, in π bonding orbitals, B 2 shows paramagnetic behaviour.

Q. The paramagnetic behaviour of $B_{2}$ is due to the presence of

$2$ unpaired electrons in $π_{b} MO$

$2$ unpaired electrons in $π^{*} MO$

$2$ unpaired electrons in $σ^{*} MO$

$2$ unpaired electrons in $σ_{b} MO$

$B_{2} = 5 + 5 = 10 e^{-}$
$= σ 1 s^{2} σ * 1 s^{2}, σ 2 s^{2} σ 2 s^{2}, π 2 p_{x}^{1}, π 2 p_{y}^{1}$
Due to the presence of 2 unpaired electrons, in $π$ bonding orbitals, $B_{2}$ shows paramagnetic behaviour.

Q. The paramagnetic behaviour of B2​ is due to the presence of

2 unpaired electrons in πb​MO

2 unpaired electrons in π∗MO

2 unpaired electrons in σ∗MO

2 unpaired electrons in σb​MO