The oxidation states of iodine in HIO 4, H 3 IO 5 and H 5 IO 6 are, respectively

Question

The oxidation states of iodine in HIO 4, H 3 IO 5 and H 5 IO 6 are, respectively (A)  +1, +3, +7  (B) +7, +7, +3 (C) +7, +7, +7 (D) +7, +5, +3

Tardigrade Admin · Accepted Answer

Oxidation state of I in HIO 4 is +7 as: 1+x+4(2) =0 x =+7 Oxidation state of I in H 3 IO 5 is +7 as. 3+x+5(-2) =0 x =+7 Oxidation state of I in H 5 IO 6 is +7 as 5+x+6(-2)=0 x=+7

Q. The oxidation states of iodine in $H I O_{4}, H_{3} I O_{5}$ and $H_{5} I O_{6}$ are, respectively

$+ 1, + 3, + 7$

$+ 7, + 7, + 3$

$+ 7, + 7, + 7$

$+ 7, + 5, + 3$

Oxidation state of $I$ in $H I O_{4}$ is $+ 7$ as :
$1 + x + 4 (2) = 0$
$x = + 7$
Oxidation state of $I$ in $H_{3} I O_{5}$ is $+ 7$ as.
$3 + x + 5 (- 2) = 0$
$x = + 7$
Oxidation state of $I$ in $H_{5} I O_{6}$ is $+ 7$ as
$5 + x + 6 (- 2) = 0$
$x = + 7$

Q. The oxidation states of iodine in HIO4​,H3​IO5​ and H5​IO6​ are, respectively

+1,+3,+7

+7,+7,+3

+7,+7,+7

+7,+5,+3