Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The oxidation states of iodine in $HIO _{4}, H _{3} IO _{5}$ and $H _{5} IO _{6}$ are, respectively

AIIMSAIIMS 2008

Solution:

Oxidation state of $I$ in $HIO _{4}$ is $+7$ as :
$1+x+4(2) =0 $
$x =+7$
Oxidation state of $I$ in $H _{3} IO _{5}$ is $+7$ as.
$3+x+5(-2) =0 $
$x =+7$
Oxidation state of $I$ in $H _{5} IO _{6}$ is $+7$ as
$5+x+6(-2)=0$
$x=+7$