Question

The oxidation state of sulphur in sodium tetrathionate$\left(N{a}_2{S}_4{O}_6\right)$ is

• A. 2
• B. 0
• C. 2.5
• D. 3.5

Answer 1

Answer: (C)

Let the oxidation state of sulphur in
$N{a}_2{S}_4{O}_6$ is $x.N{a}_2{S}_4{O}_6$
$1\times 2+4\times x+(-2)\times 6=0$
$2+4x-12=0$
$4x-10=0$
$4x=10$
$x=\frac{10}{4}=2.5$