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  4. The oxidation state of sulphur in sodium tetrathionate( Na 2 S 4 O 6) is

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Q. The oxidation state of sulphur in sodium tetrathionate$\left( Na _{2} S _{4} O _{6}\right)$ is

J & K CETJ & K CET 2008Redox Reactions

Solution:

Let the oxidation state of sulphur in
$Na _{2} S _{4} O _{6}$ is $x . N a_{2} S_{4} O_{6}$
$1 \times 2+4 \times x+(-2) \times 6=0$
$2+4 x-12=0$
$4 x-10=0$
$4 x=10$
$x=\frac{10}{4}=2.5$