The oxidation state of platinum in Na[.PtBrCl(.NO2.)(.NH3.)]. is

Question

The oxidation state of platinum in Na[.PtBrCl(.NO2.)(.NH3.)]. is (A) +2 (B) +4 (C) +6 (D) 0

Tardigrade Admin · Accepted Answer

Na[.PtBrCl(.NO2.)(.NH3.)]. Let x = oxidation state of Pt. So 1(.+1.)+x+1(.-1.)+1(.-1.)+1(.-1.)+1(.0.)=0 Or x = +2.

Q. The oxidation state of platinum in $N a [PtB r Cl (N O_{2}) (N H_{3})]$ is