Q. The oxidation state of osmium (Os) in $O s O_{4}$ is

2440 226 Redox Reactions Report Error

A

+7

4%

B

+6

7%

C

+4

12%

D

+8

78%

Solution:

$O s O_{4}$
Let O.N. of Os be $x$ then $1 \times (x) + 4 (- 2) = 0$
$∴ x = 8$