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  4. The oxidation state of osmium (Os) in OsO4 is

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Q. The oxidation state of osmium (Os) in $OsO_4$ is

Redox Reactions

Solution:

$OsO_4$
Let O.N. of Os be $x$ then $1 \times (x) + 4(-2) = 0$
$\therefore x = 8$