Q. The oxidation state of Fe in $K_{3} [F e (CN)_{6}]$ is

2404 207 JIPMERJIPMER 2016Coordination Compounds Report Error

A

+1

5%

B

+2

11%

C

+3

76%

D

-3

8%

Solution:

$K_{3} [F e (CN)_{6}]$
Let $x$ be the oxidation state of Fe.
$∴ x + 6 (- 1) = - 3 \Rightarrow x = + 3$