Question

The oxidation potential of a hydrogen electrode at $pH=10\&p{H}_2=1$ atm will be :-

• A. 0.059 V
• B. 0.59 V
• C. 0.00 V
• D. 0.51 V

Answer 1

Answer: (B)

$E_{OP}=E_{OP}^{\circ }-\frac{0.059}{1}\log \frac{\left[H^{+}\right]}{p_{H_2}^{1/2}}$
$\left[H^{+}\right]=10^{-10},P_H^2=1$
$E_{OP}=0.59V$