Question

The oxidation potential of a hydrogen electrode at $pH =10\, \& \,pH _{2}=1$ atm will be :-

• A. 0.059 V
• B. 0.59 V
• C. 0.00 V
• D. 0.51 V

Answer 1

Answer: (B)

$E _{ OP }= E _{ OP }^{\circ}-\frac{0.059}{1} \log \frac{\left[ H ^{+}\right]}{ p _{ H _{2}}^{1 / 2}}$
$\left[ H ^{+}\right]=10^{-10}, P _{ H }^{2}=1$
$E _{ OP }=0.59 \,V$