The oxidation numbers of hydrogen in K H , MgH 2 and NaH are respectively

Question

The oxidation numbers of hydrogen in K H , MgH 2 and NaH are respectively (A) + 2, + 1 and - 2 (B) + 1, + 1 and + 1 (C) - 1, - 1 and - 1 (D) - 2, - 3 and - 1

Tardigrade Admin · Accepted Answer

Hydrogen is present as hydride ion in these molecules i.e. Oxidation state is - 1.

Q. The oxidation numbers of hydrogen in KH,MgH2​ and NaH are respectively

+ 2, + 1 and - 2

+ 1, + 1 and + 1

- 1, - 1 and - 1

- 2, - 3 and - 1

Hydrogen is present as hydride ion in these molecules i.e. Oxidation state is - 1.

Q. The oxidation numbers of hydrogen in $KH, M g H_{2}$ and $N a H$ are respectively