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Tardigrade
Question
Chemistry
The oxidation number of xenon in XeOF2 is
Q. The oxidation number of xenon in
X
e
O
F
2
is
2095
204
The p-Block Elements - Part2
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A
Zero
14%
B
2
2%
C
4
81%
D
3
2%
Solution:
Suppose the oxidation state of
X
e
is
x
.
X
e
O
F
2
x
+
(
−
2
)
+
2
(
−
1
)
=
0
⇒
x
−
2
−
2
⇒
x
=
4