Question

The oxidation number of sulphur is $-4$ in

• A. $H_{2}S$
• B. $C{S}_2$
• C. $N{a}_{2}S{O}_4$
• D. $N{a}_{2}S{O}_3$

Answer 1

Answer: (A), (B), (C), (D)

The oxidation number of S in given compounds are as follows :
$(i)H_{2}S$
Let the oxidation state of S be $x$
$\therefore 2+x=0$
$x=-2$
$(ii)C{S}_2$
$4+2x=0\Rightarrow x=-2$
$(iii)N{a}_{2}S{O}_4$
$2(+1)+x+4(-2)=0$
$2+x-8=0$
$x=+6$
$(iv)N{a}_{2}S{O}_3$
$2(+1)+x+3(-2)=0$
$2+x-6=0$
$x=+4$