The oxidation number of S in H2S2O8 is

Question

The oxidation number of S in H2S2O8 is (A) + 2 (B) + 4 (C) + 6 (D) + 7

Tardigrade Admin · Accepted Answer

The chemical structure of H2S2O8 is as follows: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/1307446d004640e3712f70d50e29fd24-.jpeg" /> So the oxidation number of S should be: 2 × (+l) + 2 × X + 6 × (-2) = o or X = +6 (for H) (forS) (for O)(for O - O)

Q. The oxidation number of S in $H_{2} S_{2} O_{8}$ is

+ 2

+ 4

+ 6

+ 7

The chemical structure of $H_{2} S_{2} O_{8}$ is as follows:

So the oxidation number of S should be:
$2 \times (+ l) + 2 \times X + 6 \times (- 2) = o or X = + 6$
(for H) (forS) (for O)(for O - O)

Q. The oxidation number of S in H2​S2​O8​ is

+ 2

+ 4

+ 6

+ 7

The chemical structure of H2​S2​O8​ is as follows: So the oxidation number of S should be: 2×(+l)+2×X+6×(−2)=oorX=+6 (for H) (forS) (for O)(for O - O)

Q. The oxidation number of S in $H_{2} S_{2} O_{8}$ is

The chemical structure of $H_{2} S_{2} O_{8}$ is as follows:

So the oxidation number of S should be:
$2 \times (+ l) + 2 \times X + 6 \times (- 2) = o or X = + 6$
(for H) (forS) (for O)(for O - O)