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Q.
The oxidation number of S in $H_{2}S_{2}O_{8}$ is
Redox Reactions
Solution:
The chemical structure of $H_{2}S_{2}O_{8}$ is as follows:
So the oxidation number of S should be:
$2 \times (+l) + 2 \times X + 6 \times (-2) = o\,or\, X = +6$
(for H) (forS) (for O)(for O - O)
