The oxidation number of platinum in [Pt(NH3)5Cl]Cl3 is

Question

The oxidation number of platinum in [Pt(NH3)5Cl]Cl3 is (A) 2 (B) 3 (C) 4 (D) 6

Tardigrade Admin · Accepted Answer

Consider the given compound, [ Pt ( NH 3)5 Cl ] Cl 3 x+5 × 0+(-1)+(3 ×-1)=0 x+0-1-3=0 x-4=0 x=+4 ∴ The oxidation of platinum in the given compound is +4

Q. The oxidation number of platinum in $[Pt (N H_{3})_{5} Cl] C l_{3}$ is

2

3

4

6

Consider the given compound, $[Pt (N H_{3})_{5} Cl] C l_{3}$
$x + 5 \times 0 + (- 1) + (3 \times - 1) = 0$
$x + 0 - 1 - 3 = 0$
$x - 4 = 0$
$x = + 4$
$∴$ The oxidation of platinum in the given compound is $+ 4$

Q. The oxidation number of platinum in [Pt(NH3​)5​Cl]Cl3​ is

2

3

4

6

Consider the given compound, [Pt(NH3​)5​Cl]Cl3​ x+5×0+(−1)+(3×−1)=0 x+0−1−3=0 x−4=0 x=+4 ∴ The oxidation of platinum in the given compound is +4

Q. The oxidation number of platinum in $[Pt (N H_{3})_{5} Cl] C l_{3}$ is

Consider the given compound, $[Pt (N H_{3})_{5} Cl] C l_{3}$
$x + 5 \times 0 + (- 1) + (3 \times - 1) = 0$
$x + 0 - 1 - 3 = 0$
$x - 4 = 0$
$x = + 4$
$∴$ The oxidation of platinum in the given compound is $+ 4$