Tardigrade
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Tardigrade
Question
Chemistry
The oxidation number of platinum in [Pt( C 2 H 4) Cl 3]-is:
Q. The oxidation number of platinum in
[
Pt
(
C
2
H
4
)
C
l
3
]
−
is:
1546
227
J & K CET
J & K CET 2000
Report Error
A
1
B
2
C
3
D
4
Solution:
Let the oxidation state of Pt is
x
in
[
Pt
(
C
2
H
4
)
C
l
3
]
−
x
+
0
+
3
(
−
1
)
=
−
1
x
+
0
−
3
=
−
1
x
=
+
2