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Tardigrade
Question
Chemistry
The oxidation number of oxygen in KO3, Na2O2 is
Q. The oxidation number of oxygen in
K
O
3
,
N
a
2
O
2
is
1949
209
Redox Reactions
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A
3, 2
15%
B
1, 0
8%
C
0, 1
11%
D
-0.33, -1
65%
Solution:
O.N. of O in
K
O
3
=
1
+
3
x
=
0
∴
x
=
−
1/3
=
−
0.33
O.N. of O in
N
a
2
O
2
=
2
×
1
+
2
x
=
0
∴
x
=
−
1