Question

The oxidation number of nitrogen in $NaN{O}_2$ is :

• A. +3
• B. + 5
• C. -3
• D. -5

Answer 1

Answer: (A)

Let the oxidation number of nitrogen in $NaN{O}_2$ is $x$
$\therefore 1+x+2(-2)=0$
$1+x-4=0$
$x=+3$