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  4. The oxidation number of nitrogen in NaNO 2 is :

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Q. The oxidation number of nitrogen in $NaNO _{2}$ is :

AFMCAFMC 2006

Solution:

Let the oxidation number of nitrogen in $NaNO _{2}$ is $x$
$\therefore 1+x+2(-2)=0$
$1+x-4=0 $
$x=+3$