Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The oxidation number of Mn in the product formed on strongly heating Mn 2 O 7 is .
Q. The oxidation number of
M
n
in the product formed on strongly heating
M
n
2
O
7
is ______.
1790
175
Redox Reactions
Report Error
Answer:
4
Solution:
2
M
n
2
O
7
Δ
4
M
n
O
2
+
3
O
2
∴
Oxidation number of
M
n
O
2
is
⇒
x
+
2
×
(
−
2
)
=
0
⇒
x
=
+
4