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Tardigrade
Question
Chemistry
The oxidation number of Fe in [Fe(CN)6]3- ion is
Q. The oxidation number of Fe in
[
F
e
(
CN
)
6
]
3
−
ion is
3011
221
Redox Reactions
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A
+2
8%
B
+ 3
76%
C
- 2
8%
D
- 3
8%
Solution:
Let O.N. of Fe in
[
F
e
(
CN
)
6
]
3
−
is x
O.N. of C
(
N
−
1
= -1)
= x + 6(-1) = -3
or x= +3