Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The oxidation number of Fe in Fe3O4 is
Q. The oxidation number of
F
e
in
F
e
3
O
4
is
1998
215
BHU
BHU 2007
Report Error
A
+8/3
B
+3/8
C
-8/3
D
-3/8
Solution:
Let the oxidation state of
F
e
is '
x
'
F
e
3
O
4
=
0
3
x
+
4
(
−
2
)
=
0
3
x
−
8
=
0
x
=
3
8