Q. The oxidation number of Cr in $C r O_{5}$ is

1188 218 JamiaJamia 2011 Report Error

A

2

B

4

C

6

D

8

Solution:

Structure of $C r O_{5}$ is as follows
$x + 1 \times (- 2) + 4 (- 1) = 0$ $x - 2 - 4 = 0$ or $x = + 6$

Solution Image