Question

The oxidation number of $Cr$ in $Cr{O}_{2}C{l}_2$ is

• A. + 2
• B. + 3
• C. + 4
• D. + 6

Answer 1

Answer: (D)

Let the oxidation number of $Cr$ in $Cr{O}_{2}C{l}_2$ is $x$.
$x+2(-2)+2(-1)=0$
$x-4-2=0$
$x-6=0$
$x=6$
So, the oxidation number of $Cr$ in $Cr{O}_{2}C{l}_2$ is $+6$.