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Q. The oxidation number of $Cr$ in $CrO _{2} Cl _{2}$ is

AMUAMU 2002

Solution:

Let the oxidation number of $Cr$ in $CrO _{2} Cl _{2}$ is $x$.
$x+2(-2)+2(-1)=0 $
$x-4-2=0 $
$x-6=0$
$x=6$
So, the oxidation number of $Cr$ in $CrO _{2} Cl _{2}$ is $+6$.