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Tardigrade
Question
Chemistry
The oxidation number of Cl in CaOCl 2 is
Q. The oxidation number of
Cl
in
C
a
OC
l
2
is
98
152
Redox Reactions
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A
−
1
and
+
1
B
+
2
C
−
2
D
None
Solution:
C
a
2
+
(
OC
l
1
−
)
C
l
1
−
OC
l
⊖
:
−
2
+
x
=
−
1
⇒
x
=
+
1
C
l
⊖
:
−
1
Oxidation states of
Cl
are
−
1
and
+
1