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  4. The oxidation number of Cl in CaOCl 2 is

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Q. The oxidation number of $Cl$ in $CaOCl _2$ is

Redox Reactions

Solution:

$Ca ^{2+}\left( OCl ^{1-}\right) Cl ^{1-}$
$OCl ^{\ominus}:-2+x=-1 \Rightarrow x=+1$
$Cl ^{\ominus}:-1$
Oxidation states of $Cl$ are $-1$ and $+1$