The oxidation number of chromium in CrO5 is

Question

The oxidation number of chromium in CrO5 is (A)  +6  (B)  +5  (C)  +10  (D)  0

Tardigrade Admin · Accepted Answer

CrO 5 has following structure: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/ffd0181ce17fdaa8c66ba350776c9d3e-.png" /> Thus, Cr O 4 ⋅ O x+(-1) × 4+(-2)=0 due to peroxide linkage x - 4 - 2 = 0 ∴ =+6

Q. The oxidation number of chromium in $C r O_{5}$ is

$+ 6$

$+ 5$

$+ 10$

$0$

$C r O_{5}$ has following structure :

Thus, $C r O_{4} \cdot O$

$x + (- 1) \times 4 + (- 2) = 0$

due to peroxide linkage

$x - 4 - 2 = 0$

$∴ = + 6$

Q. The oxidation number of chromium in CrO5​ is

+6

+5

+10

0

CrO5​ has following structure : Thus, CrO4​⋅O x+(−1)×4+(−2)=0 due to peroxide linkage x−4−2=0 ∴=+6

Q. The oxidation number of chromium in $C r O_{5}$ is

$+ 6$

$+ 5$

$+ 10$

$0$

$C r O_{5}$ has following structure :

Thus, $C r O_{4} \cdot O$

$x + (- 1) \times 4 + (- 2) = 0$

due to peroxide linkage

$x - 4 - 2 = 0$

$∴ = + 6$