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Tardigrade
Question
Chemistry
The oxidation number of C in sucrose C12H22O11 is
Q. The oxidation number of C in sucrose
C
12
H
22
O
11
is
2602
244
Redox Reactions
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A
+4
4%
B
+3
10%
C
+2
10%
D
Zero
76%
Solution:
Let O.N. of C in
C
12
H
22
O
11
=
12
×
x
+
22
+
11
(
−
2
)
=
0
,
x
=
0