The oxidation number and the electronic configuration of sulphur in H2SO4 is

Question

The oxidation number and the electronic configuration of sulphur in H2SO4 is (A) + 6; 1s22s22p6 (B) + 2; 1s22s22p63s23p2 (C) + 3; 1s22s22p63s23p1 (D) + 4; 1s22s22p63s2

Tardigrade Admin · Accepted Answer

H2 overset*SO4 2 × (+ 1) × x + 4 × (- 2) = 0 +2 + x -8 = 0; x = 8 - 2 = + 6 Electronic configuration of sulphur in H2SO4 is 1s2, 2s2, 2p6.

Q. The oxidation number and the electronic configuration of sulphur in $H_{2} S O_{4}$ is

$+ 6; 1 s^{2} 2 s^{2} 2 p^{6}$

$+ 2; 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{2}$

$+ 3; 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{1}$

$+ 4; 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$

$H_{2} S * O_{4}$
$2 \times (+ 1) \times x + 4 \times (- 2) = 0$
$+ 2 + x - 8 = 0; x = 8 - 2 = + 6$
Electronic configuration of sulphur in $H_{2} S O_{4}$ is $1 s^{2}, 2 s^{2}, 2 p^{6}$ .

Q. The oxidation number and the electronic configuration of sulphur in H2​SO4​ is

+6;1s22s22p6

+2;1s22s22p63s23p2

+3;1s22s22p63s23p1

+4;1s22s22p63s2