Question

The oxidation number and the electronic configuration of sulphur in $H_{2}SO_{4}$ is

• A. $+ 6; 1s^{2}2s^{2}2p^{6}$
• B. $+ 2; 1s^{2}2s^{2}2p^{6}3s^{2}3p^{2}$
• C. $+ 3; 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$
• D. $+ 4; 1s^{2}2s^{2}2p^{6}3s^{2}$

Answer 1

Answer: (A)

$H_{2} \overset{*}{S}O_{4}$
$2 \times (+ 1) \times x + 4 \times (- 2) = 0$
$+2 + x -8 = 0; x = 8 - 2 = + 6$
Electronic configuration of sulphur in $H_{2}SO_{4}$ is $1s^{2}, 2s^{2}, 2p^{6}$.