The Osmotic pressure of the aq. solution of the given solute at 27°C if depression in freezing point is 0.90° is .(Molal depression constant of water is 1.86 K mol-1 kg? Assume molality as molarity.)

Question

The Osmotic pressure of the aq. solution of the given solute at 27°C if depression in freezing point is 0.90° is .(Molal depression constant of water is 1.86 K mol-1 kg? Assume molality as molarity.) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ T f = k f × molarity, π= molarity × RT ∴ (Δ T f /π)=( k f / RT ) (0.9/π)=(1.86/0.0821 × 300) π=11.918 atm

Q. The Osmotic pressure of the aq. solution of the given solute at $2 7^{\circ} C$ if depression in freezing point is $0.9 0^{\circ}$ is ______.(Molal depression constant of water is $1.86 K m o l^{- 1} k g$ ? Assume molality as molarity.)

$Δ T_{f} = k_{f} \times$ molarity,

$π =$ molarity $\times RT$

$∴ \frac{Δ T _{f}}{π} = \frac{k _{f}}{RT}$

$\frac{0.9}{π} = \frac{1.86}{0.0821 \times 300}$

$π = 11.918 a t m$

Q. The Osmotic pressure of the aq. solution of the given solute at 27∘C if depression in freezing point is 0.90∘ is ______.(Molal depression constant of water is 1.86Kmol−1kg? Assume molality as molarity.)

ΔTf​=kf​× molarity, π= molarity ×RT ∴πΔTf​​=RTkf​​ π0.9​=0.0821×3001.86​ π=11.918atm

Q. The Osmotic pressure of the aq. solution of the given solute at $2 7^{\circ} C$ if depression in freezing point is $0.9 0^{\circ}$ is ______.(Molal depression constant of water is $1.86 K m o l^{- 1} k g$ ? Assume molality as molarity.)

$Δ T_{f} = k_{f} \times$ molarity,

$π =$ molarity $\times RT$

$∴ \frac{Δ T _{f}}{π} = \frac{k _{f}}{RT}$

$\frac{0.9}{π} = \frac{1.86}{0.0821 \times 300}$

$π = 11.918 a t m$