The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL -1 is (Molar mass of glucose =180 g mol -1 R =0.083 L bar K-1 mol -1 ) (Nearest integer)

Question

The osmotic pressure of blood is 7.47 bar at 300 K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL -1 is (Molar mass of glucose =180 g mol -1 R =0.083 L bar K-1 mol -1 ) (Nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

π= C . R . T 7.47= C × 0.083 × 300 C =0.3 M =0.3 × 180 gL -1 =54 gL -1

Q. The osmotic pressure of blood is 7.47 bar at 300K. To inject glucose to a patient intravenously, it has to be isotonic with blood. The concentration of glucose solution in gL−1 is____ (Molar mass of glucose =180gmol−1 R=0.083LbarK−1mol−1 ) (Nearest integer)

π=C.R.T 7.47=C×0.083×300 C=0.3M =0.3×180gL−1 =54gL−1

$π = C . R . T$
$7.47 = C \times 0.083 \times 300$
$C = 0.3 M$
$= 0.3 \times 180 g L^{- 1}$
$= 54 g L^{- 1}$