The oscillating magnetic field in a plane electromagnetic wave is given by By=5 × 10-6 sin 1000 π(5 x-4 × 108 t ) T. The amplitude of electric field will be :

Question

The oscillating magnetic field in a plane electromagnetic wave is given by By=5 × 10-6 sin 1000 π(5 x-4 × 108 t ) T. The amplitude of electric field will be : (A) 15 × 102 Vm -1 (B) 5 × 10-6 Vm -1 (C) 16 × 1012 Vm -1 (D) 4 × 102 Vm -1

Tardigrade Admin · Accepted Answer

B 0=5 × 10-6 v = Speed of wave =(4 × 108/5)=8 × 107 [∴ v =( w / k )] E 0= vB 0=40 × 101 =4 × 102 V / m

Q. The oscillating magnetic field in a plane electromagnetic wave is given by $B_{y} = 5 \times 1 0^{- 6} sin 1000 π (5 x - 4 \times 1 0^{8} t) T$ . The amplitude of electric field will be :

$15 \times 1 0^{2} V m^{- 1}$

$5 \times 1 0^{- 6} V m^{- 1}$

$16 \times 1 0^{12} V m^{- 1}$

$4 \times 1 0^{2} V m^{- 1}$

$B_{0} = 5 \times 1 0^{- 6}$
$v =$ Speed of wave $= \frac{4 \times 1 0 ^{8}}{5} = 8 \times 1 0^{7}$
$[∴ v = \frac{w}{k}]$
$E_{0} = v B_{0} = 40 \times 1 0^{1}$
$= 4 \times 1 0^{2} V / m$

Q. The oscillating magnetic field in a plane electromagnetic wave is given by By​=5×10−6sin1000π(5x−4×108t)T. The amplitude of electric field will be :

15×102Vm−1

5×10−6Vm−1

16×1012Vm−1

4×102Vm−1